11p^2-4p^2=21p+13p

Solution for 11p^2-4p^2=21p+13p equation:

11p^2-4p^2=21p+13p

We move all terms to the left:

11p^2-4p^2-(21p+13p)=0

We add all the numbers together, and all the variables

11p^2-4p^2-(+34p)=0

We add all the numbers together, and all the variables

7p^2-(+34p)=0

We get rid of parentheses

7p^2-34p=0

a = 7; b = -34; c = 0;
Δ = b2-4ac
Δ = -342-4·7·0
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-34}{2*7}=\frac{0}{14}
=0
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+34}{2*7}=\frac{68}{14}
=4+6/7
$